How martingale craps works on the pass line
You bet $5 on the pass line. If the shooter wins, you collect $5 and bet $5 again. If the shooter loses, the next pass line bet is $10. Lose again and it is $20, then $40, then $80. Whenever a bet finally wins, it pays enough to cover every loss in the chain plus one $5 unit of profit.
That pattern is why martingale craps feels safe. Most sequences end fast, since the pass line wins almost half the time. Your session log fills with small $5 profits, one after another. It takes a long run of losses to hurt you, and on most nights the long run simply does not arrive before you leave.
The pass line suits the system in one narrow way: it pays even money and has no pushes, so a win always resolves the chain. Its house edge of 1.414% is also one of the lowest flat bets on the craps layout. Neither fact changes what happens when the losses keep coming.
The odds of 5, 7 and 10 losses in a row
A pass line bet loses 251 of every 495 decisions, a loss rate of 50.71%. Each decision is independent, so the chance of several losses in a row is that figure multiplied by itself. The table below shows how quickly the streak probability shrinks, and how quickly the martingale bet grows.
| Losses in a row | Chance | About 1 in | Next bet from $5 | Lost so far |
|---|---|---|---|---|
| 3 | 13.04% | 8 | $40 | $35 |
| 5 | 3.35% | 30 | $160 | $155 |
| 7 | 0.862% | 116 | $640 | $635 |
| 8 | 0.437% | 229 | $1,280 | $1,275 |
| 10 | 0.112% | 890 | $5,120 | $5,115 |
Those chances apply to every new sequence, not once per night. Play 200 pass line decisions and you have about a 57.5% chance of meeting at least one run of seven losses. At an average of 3.4 rolls per decision, 200 decisions is well under an evening at a busy table.
The streaks are longer than intuition says
People underestimate streaks because they picture a single sequence. Over 500 decisions the chance of at least one run of five losses is close to 100%, and even ten in a row turns up about 24% of the time. Martingale craps does not fail on an unusual night. It fails on an ordinary one, eventually.
Where the table limit ends the run
Every craps table has a maximum bet, printed on the placard next to the minimum. Suppose you play a $5 table with a $1,000 maximum. After seven losses you have lost $635 and the system asks for $640, which is allowed. Lose that one too and the next step would be $1,280. The table will not take it.
At that point the chain is broken. You are down $1,275 and the best the rules now allow is a $1,000 bet that, if it wins, still leaves you $275 short. The martingale promise of always winning one unit back is gone. The run of eight losses costs roughly 255 of the $5 wins that came before it.
That trade is the whole of martingale craps in one sentence. You win $5 about 99.56% of the time a sequence starts, and you lose $1,275 about 0.44% of the time. Multiply both out and the loss side is larger, by exactly the house edge on all the money you wagered.
Bankroll: the limit that usually arrives first
For most players the table maximum is not the real wall. The wallet is. Few people sit at a $5 table carrying $1,275 they are ready to lose on one sequence, and fewer still want to push $640 onto one pass line bet after six losses. Martingale craps demands nerve at exactly the wrong moment.
A $300 bankroll at a $5 table survives only five losses, since the sixth step needs $160 and you have $145 left. From the table above, five straight losses show up about once every 30 sequences. That is not a rare disaster; it is a normal part of an evening. Our page on bankroll management sizes sessions properly.
There is a behavioural cost too. Chasing losses by raising bet size is the pattern problem-gambling counsellors warn about most. If doubling up starts to feel like a way of getting money back rather than a game, stop and call 1-800-GAMBLER, or read our responsible gambling page for state resources.
What the martingale really costs per hour
The house edge on the pass line is 1.41% of every dollar wagered. Martingale craps does not change that percentage. It changes how many dollars you wager, because the doubled bets after losses make your average bet larger than the $5 base. More money in action at the same edge means a higher expected cost per hour.
Compare it with the simplest craps betting strategy there is: $5 on the pass line with full odds behind it. The odds bet has no house edge, so the combined edge drops to 0.374% at a 3-4-5x table. You get calmer swings and a lower price, and nothing needs to double. Try both in our strategy lab.
The race at the top of this page shows the difference over many simulated shooters. The martingale craps line climbs steadily for a while and then drops in steps, each one a streak that met the limit. The flat pass line with odds wanders around its starting point and drifts down slowly, as the smaller edge predicts.
Best craps strategy alternatives to doubling up
If you want the best mathematical craps strategy, bet the pass line or don’t pass and take the largest odds you can afford. Add a come bet or two for more action, as in the 3 point molly. Every other pattern costs more per dollar, and no bet sizing plan can close the gap.
That is also the honest answer to how to win at craps. Nobody wins over the long run at a fixed edge, but you can keep the edge small, keep bet sizes steady and set a stopping point before you sit down. Good sessions come from luck on cheap bets, not from a progression that eventually meets the maximum.
Licensed online tables in New Jersey, Pennsylvania, Michigan and West Virginia post their minimum and maximum in each game’s rules. Games regulated by bodies such as the NJ Division of Gaming Enforcement cannot remove that maximum for you. Before any martingale craps plan, read the maximum and count how many losses it actually allows.